| | 1 | = Ex17.c = |
| | 2 | {{{#!C |
| | 3 | /* |
| | 4 | Large Scale Computing |
| | 5 | 2D Heat/Mass Transfer |
| | 6 | ex17.c : Numerical Analysis |
| | 7 | Solve for |
| | 8 | d2c/dx2 + d2c/dy2 + 1 = 0 |
| | 9 | With the boundary conditions of c = 0 |
| | 10 | along lines of x=1,-1, and y=1, and -1 |
| | 11 | */ |
| | 12 | #include<stdio.h> |
| | 13 | #include<stdlib.h> |
| | 14 | #include<math.h> |
| | 15 | |
| | 16 | #define NUM 20 /* number of points for x and y*/ |
| | 17 | #define TOL 1.0e-12 /* convergence tolerance */ |
| | 18 | |
| | 19 | int main(void ){ |
| | 20 | int i,j,k,n,ie,iw,in,is; |
| | 21 | double x,y,dx,w,err; |
| | 22 | double cnc[NUM * NUM]; /* define 1D array of length NUM * NUM */ |
| | 23 | FILE *fp; |
| | 24 | |
| | 25 | /*assuming dx = dy : domain is 2x2 */ |
| | 26 | dx = 2.0 / (double)(NUM - 1); |
| | 27 | |
| | 28 | /* Initialize */ |
| | 29 | for (n = 0 ; n < NUM * NUM ; n++){ |
| | 30 | cnc[n] = 0.0; |
| | 31 | } |
| | 32 | |
| | 33 | /* computing for C with Gauss-Seidel */ |
| | 34 | k = 0; |
| | 35 | while(1){ |
| | 36 | err = 0.0; |
| | 37 | for (n = 0 ; n < NUM * NUM ; n++){ |
| | 38 | i = n % NUM; /* i is residual */ |
| | 39 | j = n / NUM; /* j is division */ |
| | 40 | if (i == 0) continue; /*skip left end*/ |
| | 41 | if (i == NUM-1) continue; /*skip right end*/ |
| | 42 | if (j == 0) continue; /*skip bottom end*/ |
| | 43 | if (j == NUM-1) continue; /*skip top end*/ |
| | 44 | |
| | 45 | ie = n + 1; |
| | 46 | iw = n - 1; |
| | 47 | in = n + NUM; |
| | 48 | is = n - NUM; |
| | 49 | w = 0.25 * (dx * dx + cnc[ie] + cnc[iw] + cnc[in] + cnc[is]); |
| | 50 | err += (w - cnc[n]) * (w - cnc[n]); |
| | 51 | cnc[n] = w; |
| | 52 | } |
| | 53 | k++; |
| | 54 | if (err < TOL) break; |
| | 55 | } |
| | 56 | printf("# of Iteration=%d\n",k); |
| | 57 | |
| | 58 | /* Output Result */ |
| | 59 | fp = fopen("res.dat","w"); |
| | 60 | if (fp == NULL){ |
| | 61 | printf("File could not create\n"); |
| | 62 | exit(-1); |
| | 63 | } |
| | 64 | |
| | 65 | for (i = 0 ;i < NUM ; i++){ |
| | 66 | for (j = 0 ; j < NUM ; j++){ |
| | 67 | x = -1.0 + 2.0 * (double)i / (double)(NUM - 1); |
| | 68 | y = -1.0 + 2.0 * (double)j / (double)(NUM - 1); |
| | 69 | fprintf(fp,"%e %e %e\n",x,y,cnc[i + NUM * j]); |
| | 70 | } |
| | 71 | } |
| | 72 | fclose(fp); |
| | 73 | |
| | 74 | printf("Done\n"); |
| | 75 | } |
| | 76 | }}} |